\(\mathrm {log_2log_\sqrt {e}e^2 =?}\)
| May 9, 2023 | গাণিতিক যুক্তি, , 41 BCS Preliminary
- \(-2\)
- \(-1\)
- \(1\)
- \(2\)
\begin{aligned} & \log _2 \log _{\sqrt{\mathrm{e}}} \mathrm{e}^2 \\ & =\log _2 2 \log _{\sqrt{\mathrm{e}}} \mathrm{e} \\ & =\log _2 2 \log _{\sqrt{\mathrm{e}}}(\sqrt{\mathrm{e}})^2 \\ & =\log _2 4 \log _{\sqrt{\mathrm{e}}} \sqrt{\mathrm{e}} \\ & =\log _2(4 \times 1) \\ & =\log _2 4 \\ & =\log _2 2^2 \\ & =2 \log _2 2 \\ & =2 \times 1 \\ & =2\end{aligned}
